18.96

Question

Identify each of the following reactions in the β oxidation of palmitic acid, a C16 fatty acid, as (1) activation, (2) first oxidation, (3) hydration, (4) second oxidation, (5) cleavage (thiolysis): 

a. Palmitoyl CoA and FAD form α,β unsaturated fatty acids.

b. β-ketopalmitoyal CoA forms myristoyl CoA and acetyl CoA.

c. Palmitic acid, CoA, and ATP from palmitoyal CoA .

d. α,β unsaturated  palmitoyal CoA  and water from  β -hydroxy palmitoyal CoA.

e. β -hydroxy palmitoyal CoA and NAD+ from β-ketopalmitoyal CoA and NADH + H+

Step-by-Step Solution

Verified
Answer

a. first oxidation

b. Cleavage

c. Activation

d. Hydration followed by Second oxidation

e. Second oxidation

1Step 1: Part (a) Given information

Palmitoyl CoA and FAD form α,β unsaturated fatty acids. 

2Step 1: Part (a) Explanation

The first step is oxidation. 

The dehydrogenation of fatty acyl CoA forms a trans double bond between alpha and beta carbon. In this step, an electron is transferred to FAD.


3Step 1: Part (b) Given information

β-ketopalmitoyal CoA forms myristoyl CoA and acetyl CoA. 

4Step 2: Part (b) Explanation

This is the fifth step which is cleavage which is known as thiolysis.


5Step 1: Part (c) Explanation


Palmitic acid, CoA, and ATP from palmitoyal CoA . 


It is the first step that is the activation.


6Step 1: Part (d) Given information

α,β unsaturated palmitoyal CoA and water from β -hydroxy palmitoyal CoA. 

7Step 2; Part (d) Explanation

This step is the hydration process followed by second oxidation.




Second oxidation:




8Step 1:Part (e) Given information

β -hydroxy palmitoyal CoA and NAD+ from β-ketopalmitoyal CoA and NADH + H+

9Step 2: Part (e) Explanation

This step is also second oxidation.