18.96
Question
Identify each of the following reactions in the β oxidation of palmitic acid, a C16 fatty acid, as (1) activation, (2) first oxidation, (3) hydration, (4) second oxidation, (5) cleavage (thiolysis):
a. Palmitoyl CoA and FAD form unsaturated fatty acids.
b. -ketopalmitoyal CoA forms myristoyl CoA and acetyl CoA.
c. Palmitic acid, CoA, and ATP from palmitoyal CoA .
d. unsaturated palmitoyal CoA and water from -hydroxy palmitoyal CoA.
e. -hydroxy palmitoyal CoA and NAD+ from -ketopalmitoyal CoA and NADH + H+
Step-by-Step Solution
Verifieda. first oxidation
b. Cleavage
c. Activation
d. Hydration followed by Second oxidation
e. Second oxidation
Palmitoyl CoA and FAD form unsaturated fatty acids.
The first step is oxidation.
The dehydrogenation of fatty acyl CoA forms a trans double bond between alpha and beta carbon. In this step, an electron is transferred to FAD.
-ketopalmitoyal CoA forms myristoyl CoA and acetyl CoA.
This is the fifth step which is cleavage which is known as thiolysis.
Palmitic acid, CoA, and ATP from palmitoyal CoA .
It is the first step that is the activation.
unsaturated palmitoyal CoA and water from -hydroxy palmitoyal CoA.
This step is the hydration process followed by second oxidation.
Second oxidation:
-hydroxy palmitoyal CoA and NAD+ from -ketopalmitoyal CoA and NADH + H+
This step is also second oxidation.