Q. 158 - Intermediate Algebra

Question

Simplify ${\left(\frac{k^{-2}{k}^8}{k^3}\right)}^2$

Step-by-Step Solution

Answer

Simplified expression is $k^6$

Step 1 Given information

Simplify${\left(\frac{k^{-2}{k}^8}{k^3}\right)}^2$

Step 2 Simplification

Here

$$\begin{gathered} {\left(\frac{k^{-2}{k}^8}{k^3}\right)}^2={\left(k^{-2+8-3}\right)}^2 \\ ={\left(k^3\right)}^2 \\ =k^{3\times 2} \\ =k^6 \end{gathered}$$